Article "Кубок газеты «Молот»" in Russian Wikipedia has 7.3 points for quality (as of November 1, 2023). The article contains 1 references and 3 sections.
In October 2023 the article "Кубок газеты «Молот»" was edited by 1 authors in Russian Wikipedia and written by 1 authors in all languages.
Since the creation of article "Кубок газеты «Молот»", its content was written by 5 registered users of Russian Wikipedia and edited by 5 registered Wikipedia users in all languages.
The article is cited 8 times in Russian Wikipedia and cited 8 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | Russian: #296119 01.2014 |
Global: #3093093 01.2014 |
| Best Rank | Russian: #30563 06.2017 |
Global: #905487 06.2017 |
On 28 April 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: YouTube, Fallout, Facebook, Baby Reindeer, Challengers, Premier League, Fallout, deaths in 2024, Queen of Tears, Arsenal F.C..
In Russian Wikipedia the most popular articles on that day were: Яндекс, YouTube, Вход Господень в Иерусалим, ВКонтакте, Иванов, Тимур Вадимович, Фоллаут (телесериал), Банионис, Донатас Юозович, Wildberries, Россия, Сёгун (мини-сериал, 2024).
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(17.66+0.55+0+15+3.09)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
